Documents

IB Chem 1 Assess Cwsm1a

Categories
Published
of 4
All materials on our website are shared by users. If you have any questions about copyright issues, please report us to resolve them. We are always happy to assist you.
Related Documents
Share
Description
Ib chem
Transcript
  Chemistry for the IB Diploma Copyright Cambridge University Press 2011. All rights reserved. Page 1 of 4 Marking scheme for Core Worksheet 1 – Chapter 1 1   a  0.10 mol [1] b  0.010 mol [1] c  0.062 mol [1] d  1.6 ×  10  –3  mol [1] e  0.14 mol [1] f   0.024 mol [1] g  0.0832 mol [1] h  0.017 mol [1] i  0.023 mol [1] 2   a  120 g [1] b  4.4 g [1] c  63.8 g [1] d  8006 g [1] e  17 g [1] f   291 g [1] g  66.6 g [1] h  192 g [1] i  200 g [1] 3   a  6.64 ×  10  –24  g [1] b  2.66 ×  10  –23  g [1] c  4.04 ×  10  –23  g [1] 4   a  5.65 ×  10  –23  g [1] b  7.65 ×  10  –23  g [1] 5   a  3.34 ×  10 23  [1] b  1.88 ×  10 23  [1] c  1.36 ×  10 23  [1] 6   a  5.96 ×  10 22  [1] b  2.18 ×  10 23  [1] c  8.37 ×  10 24  [1] 7   a  56.0 [1] b  108 [1] c  254 [1]  Chemistry for the IB Diploma Copyright Cambridge University Press 2011. All rights reserved. Page 2 of 4 8   a  27.3% [1] b  79.9% [1] c  58.5% [1] d  80.0% [1] 9   a  NH 2  [1] b  HCO 2  [1] c  C 3 H 8  NO [1] 10   a  C 5 H 10  [1] b  H 2 O 2  [1] c  C 4 H 10 O 2  [1] 11   a  moles of CO 2  = 6.9044.01 = 0.157 mol [1] moles of H 2 O = 2.8318.02 = 0.157 mol [1] moles of C = 0.157 mol moles of H = 2 ×  0.157 = 0.304 mol [1] empirical formula = CH 2  [1] b  mass of C in CO 2  = 12.0144.01  ×  3.04 = 0.830 g [1] mass of H in H 2 O = 2.0218.02  ×  1.24 = 0.139 g [1] mass of O = 1.52 – (0.830 + 0.139) = 0.551 g [1] ratio of moles C : H : O is 0.0691 : 0.139 : 0.0344 whole number ratio is 2.01 : 4.04 : 1 [1] empirical formula: C 2 H 4 O [1] 12   a   2 C 4 H 10  + 13 O 2   →   8 CO 2  + 10 H 2 O [1] b  Sb 2 S 3  + 6 HCl →   2 SbCl 3  + 3 H 2 S [1] c  PbCl 4  + 2 H 2 O →  PbO 2  + 4 HCl [1] d   3 Ag + 4 HNO 3   →   3 AgNO 3  + 2 H 2 O + NO [1] e  Fe 2 O 3  + 3 CO →   2 Fe + 3 CO 2  [1] 13   a  0.1 mol [1] b  1.0 mol [1] c  0.2 mol [1] d  9.0 mol [1]  Chemistry for the IB Diploma Copyright Cambridge University Press 2011. All rights reserved. Page 3 of 4 14   a  0.089 mol [1] b  0.0089 mol [1] c  0.054 mol [1] d  0.033 mol [1] 15   a  number of moles of hydrogen = 20.02.02 = 9.90 mol moles of ammonia = 23   ×  9.90 = 6.60 mol volume of ammonia = 6.60 ×  22.4 = 148 dm 3  [1] b  number of moles of methane = 1.0016.05 = 0.0623 mol moles of CO 2  = 0.0623 mol volume of CO 2  = 0.0623 ×  22.4 = 1.40 dm 3  [1] 16   a   PV n RT  = ; 56 2.0010150108.31300 n − × × ×=×  [1] n  = 0.0120 mol [1] b   PV n RT  = ; 56 1.1010200108.31298 n − × × ×=×  [1] n  = 8.88 ×  10  –3  mol [1] 17   a  Mg [1] b  C 3 H 8  [1] 18   a  HCl [1] b  CO [1] 19   a  0.0100 mol [1] b  5.00 ×  10  –3  mol [1] 20   a  NaOH + HCl →  NaCl + H 2 O moles of HCl = 20.01000  ×  0.200 = 4.00 ×  10  –3  mol [1] moles of NaOH = 4.00 ×  10  –3  mol [1] volume of NaOH = 3 4.00100.100 − ×  = 4.00 ×  10  –2  dm 3  = 40.0 cm 3  [1]  Chemistry for the IB Diploma Copyright Cambridge University Press 2011. All rights reserved. Page 4 of 4 b  NaOH + HNO 3   →  NaNO 3  + H 2 O moles of HNO 3  = 25.01000  ×  0.125 = 3.13 ×  10  –3  mol [1] moles of NaOH = 3.13 ×  10  –3  mol [1] volume of NaOH = 3 3.13100.100 − ×  = 3.13 ×  10  –2  dm 3  = 31.3 cm 3  [1] c  2NaOH + H 2 SO 4   →  Na 2 SO 4  + 2H 2 O moles of H 2 SO 4  = 30.01000  ×  0.100 = 3.00 ×  10  –3  mol [1] moles of NaOH = 3.00 ×  10  –3   ×  2 = 6.00 ×  10  –3  mol [1] volume of NaOH = 3 6.00100.100 − ×  = 6.00 ×  10  –2  dm 3  = 60.0 cm 3  [1]

uoiupupo

Jul 23, 2017

Stochastic.ppt

Jul 23, 2017
We Need Your Support
Thank you for visiting our website and your interest in our free products and services. We are nonprofit website to share and download documents. To the running of this website, we need your help to support us.

Thanks to everyone for your continued support.

No, Thanks